What is the UPSC ranking principle in case of equal marks? What is the methodology used by the Union Public Service Commission to break a tie in marks?
If the overall marks of two or more candidates are equal, how is relative merit between such candidates decided by UPSC? Who will be given a higher rank?
The tie-breaking principle in UPSC Civil Services Exam (CSE)
The tie-breaking principle in UPSC Forest Service Exam (IFoS)
The case of equal marks often arises in various exams conducted by UPSC like Civil Services Examination. In fact, there may be 10 or 15 candidates with the same mark.
UPSC then apply ‘Tie-breaking’ principles to decide inter-se merit among candidates having the same overall marks. Then, the commission will calculate ranks based on certain criteria.
The candidate securing more marks in the Compulsory Papers and the Personality Test put together is to be ranked higher.
In a case where the marks mentioned above are equal, the candidate senior in age is to be ranked higher.
By Compulsory papers in CSE, UPSC means the common papers in CSE Mains. This includes 1 Essay Paper and 4 General Studies Papers. Optional Papers are not counted for tie-breaking.
The tie-breaking principle in UPSC Forest Service Exam (IFoS)
In UPSC Forest Services Exam, wherever two or more candidates have secured equal aggregate marks, these tie(s) is/are resolved by adopting the same formulae as in Civil Services Exam ie.
The candidate securing more marks in the Compulsory Papers and the Personality Test put together is to be ranked higher.
In a case where the marks mentioned above are equal, the candidate senior in age is to be ranked higher.
By Compulsory papers in IFoS, UPSC means the common papers in IFoS Mains. This includes 1 General English Paper and 1 General Knowledge Paper. Optional Papers are not counted for tie-breaking.
Analytics IAS will come up with such blogs so that students shall clear all their doubts.
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